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The Veterans Home of the Dep’t of the U.S. Public Health Service announced late last year that an $11.5-million capital improvement and renovation project will begin at the facility.

While the specific improvements are under consideration, officials say they want to improve housing for patients suffering from dementia, especially those with Alzheimer’s disease.

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Proof of Pythagoras Theorem

I was thinking about this problem:
“Let $x$ and $y$ be real numbers. Prove or disprove the following statements:
a) If $y$ is an integer, then so is $x+y$
b) If $x$ is an integer, then so is $x+y$
c) If $y$ is a rational number, then $x+y$ is also rational”
The question seems to suggest there is a proof of the Pythagoras Theorem by reduction.
I proved statements a) and c) as follows:
a) $\sqrt{a^2+(b-k)^2} = \sqrt{a^2+b^2-(2ak)} = \sqrt{(a+b-2k)^2 – 2k^2}$ (we can assume $0\leq k \leq a$, otherwise we would have $a\leq b$ and the statement is true).
b) Let $q$ be a real number such that $q=r-s$. Then $r+s = q+2s = q+2r-2s = q+2q-2s = 2q-2s = 2r-2s$.
Of course there are infinitely many rationals between two rationals (or any two real numbers). I think my proofs for a) and b) imply that if $x$ is an integer then $x+y$ is also an integer and

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